Cr2O3 (s) + 2 Al (s) = 2 Cr (s) + Al2O3 (s) Cr can be prepared by reacting the o
ID: 951526 • Letter: C
Question
Cr2O3 (s) + 2 Al (s) = 2 Cr (s) + Al2O3 (s) Cr can be prepared by reacting the oxide Cr2O3 with Al. If 150 g of Al are reacted. How much chromium metal will be produced? (Check for limiting reactant) Cr2O3 (s) + 2 Al (s) = 2 Cr (s) + Al2O3 (s) Cr can be prepared by reacting the oxide Cr2O3 with Al. If 150 g of Al are reacted. How much chromium metal will be produced? (Check for limiting reactant) Cr can be prepared by reacting the oxide Cr2O3 with Al. If 150 g of Al are reacted. How much chromium metal will be produced? (Check for limiting reactant)Explanation / Answer
Cr2O3 (s) + 2 Al (s) = 2 Cr (s) + Al2O3 (S)
2 moles of Al react with Cr2O3 to form 2 moles of Cr
2*27gm of Al react with Cr2O3 to form 2*52gm of Cr
150gm of Al react with Cr2O3 to form = 2*52*150/2*27 = 288.9gm of Cr
limiting reagent is Cr2O3