Consider the following utile at a specific temperature. 2NO (g) + O_2 (g) righta

Question

Consider the following utile at a specific temperature. 2NO (g) + O_2 (g) rightarrow 2 NO_2(g) Calculate the order with respect to NO and O_2. When showing the setup, use numbers from the table and not numbers such as "2" or "3". Order with respect to NO? Order with respect to O_2? Overall order? Write the rate law expression for the reaction. Calculate the rate law constant for the reaction. Calculate the amount of time it would take, in hours, for the concentration of NO to decrease from 5.00 Times 10^17 to 4.00 Times 10^16. Use the following integrated equation.

Explanation / Answer

A)

first keep [02] constant

now

when [N0] is increased by 3 times the rate of reaction is increased by 9 times

so

the order with respect to N0 is 2

now

keep [NO] constant

when [02] is increased by 2 times , the rate of reaction is increased by 2 times

so

the order with respect to 02 is 1

so

overall order = 2 + 1 = 3

B)

the rate law expression is given by

rate = k [NO]^2 [02]

C)

consider the first trail

2 x 10^16 = k [10^18]^2 [10^18]

k = 2 x 10^-38

so

the value of rate constant is 2 x 10^-38

D)

given

1/[A]2 - 1/[Ao]^2 = 2kt

so

(1/4 x 10^16)^2 - (1/5 x10^17)^2 = 2 x 2 x 10^-38 x t

t = 15525 sec

t = 15525 / 60 min

t = 258.75 min

t = 258.75 / 60 hr

t = 4.3125 hr

so

time taken is 4.3125 hours

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