C_6H_5COOH\' equivalent H^+ C_6H_5COO^- The pH of a 0.220 M C_6H_5COOH solution

Question

C_6H_5COOH' equivalent H^+ C_6H_5COO^- The pH of a 0.220 M C_6H_5COOH solution is 2.42. Write the ionization constant expression for an aqueous solution of benzoic acid. Calculate Ka for benzoic acid. Determine the percent ionization of benzoic acid. HOBr equivalent H^+ OBr For a 0.033 M HOBr solution, Ka is 2.5 times 10^-9. Write an equation for the ionization constant of HOBr Determine the hydrogen ion concentration of this solution Calculate the pH of the solution Calculate the percent ionization of the acid In a different experiment, 0.010 M NaOH is added to the initial acid solution. Assume no change in volume. Calculate the hydrogen ion concentration of this solution. pH of the solution percent ionization of the acid

Explanation / Answer

1a)

Ka = products / reactants

Ka =[C6H5COO-][H+]/[C6H5COOH]

1b)

[H+] = 10^-pH = 10^-2.42 = 0.0038

[C6H5COOH] = 0.22-0.0038 = 0.2162

then

Ka =[C6H5COO-][H+]/[C6H5COOH]

Ka = (0.0038)(0.0038)/(0.2162) = 0.00006679

%ion = [H+]/M * 100 = 0.0038/0.22*100 = 1.72727

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