How many moles of Mg_3P_2(s) can be produced from the reaction of 0.14 ml Mg(s)

Question

How many moles of Mg_3P_2(s) can be produced from the reaction of 0.14 ml Mg(s) with 0.020 mol P_2(s)? 6Mg(s) + P_4(s) rightarrow MgP_2(s) 0.047 mol 0.14 mol 0.42 mol 0.020 mol 0.040 mol Which anion will form a precipitate with Ba^2+? cl^- OH^- C-2H-3O_2^- Br^- Metal oxides react with water so produce bases hydrogen gas oxygen gas acids hydronium ions a precipitate is expected when a aqueous solution of rubidium iodide is added to an aqueous solution of calcium nitrate barium hydroxide ;laed perchlorate iron(II) chloride sodium sulfate.

Explanation / Answer

1. E. 0.040 mol

2. E. None of these

3. A. Bases

4. C. Lead perchlorate

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