Problem 19.98 Using the data in Appendix C in the textbook and given the pressur

Question

Problem 19.98 Using the data in Appendix C in the textbook and given the pressures listed, calculate G for each of the following reactions at 298 K Part A N2(9) +3H2(9)2NH3 (9) A, 3.3 atm 'Pn = 9.0 atm. PNH,-11 atm Express your answer using two significant figures. If your answer is greater than 10100, express it in terms of the base of the natural logarithm: for example, exp (200) Submit My Answers Give Up Part B N2(9) +3H2(9)-2NH3 (9) A,-3.3 atrn,An° 9.0 atm. PNH 1.1 atm Express your answer using three significant figures. kJ Submit My Answers Give Up Part C 2 N2H4 (g)+2NO2(g)-3 N2 g)4H2O (g) Ps,H.-PN02-3.5 × 10-2 atm, PN2-20 atm , Ph2o-1 atm Express your answer using two significant figures. If your answer is greater than 10100, express it in terms of the base of the natural logarithm: for example, exp (20o) Submit My Answers Give Up

Explanation / Answer

part a) Kp = [PNH3]2 / [PN2] [PH2]3

Kp = [1.1]2 / [3.3] [9.0]3    = 0.00050297 = 5.03x10-4

part b) delta G = -RT ln K { k = equilibrium cons.or disociation cons.,R= gas constant}

delta G = -8.314 x 298 K ln [5.03x10^-4] = 18817 J = 18.817 KJ

part C) Kp= [2.0]3 [1.0]4 / [3.5x10^-2]2 [3.5x10^-2]2 = 5331112 = 5.331112 x 10^6

part d) delta G = -RT ln[K] = -8.314 x 298 x ln[5331112] = -38375 J = -38.375 KJ

similarly E and F
  

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