In the electronic configuration of sulfur, 1s^2, 2S^2, 2P^2, 3S^2 3P^4, what ele

Question

In the electronic configuration of sulfur, 1s^2, 2S^2, 2P^2, 3S^2 3P^4, what electron shell member determines the valence electrons? 1, 2, 3, 1 & 2, 1 & 3 Which element would be more electronegative than chlorine Sulfur Lithium Bromine Carbon None of the these The octet rule states that an atom will form covalent bonds to achieve a complete of eight valence electron A spontaneous process will take place under a given set of conditions without any outside influence. Metals tend to gain electrons to attain the configuration of noble gases Covalent bond formation occurs between atoms of metal and non-metals. A negative ion is formed when an element losses an electron Fossil fuels bums to carbon dioxide and water is not always spontaneous in any circumstances The overall sum of the entropy changes of both the system and the surroundings must be positive, delta S universe = delta System + delta S surroundings

Explanation / Answer

1)

since the last 2+4 electrons are in s and p, the last electron shell is n = 3

2)

Cl is pretty electronegative, only Fluorine is stronger, so choose "none"

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