Consider the dissociation reaction A2( g )?2A( g ). The following pictures repre

Question

Consider the dissociation reaction A2(g)?2A(g). The following pictures represent two possible initial states and the equilibrium state of the system.

« previous | 5 of 9 Conceptual Problem 17.34 What are the signs (+,-, or 0) of H, S, and G when the system goes from initial state 1 to the equilibrium state? Ex plain. Is this a spontaneous process? Consider the dissociation reaction A2(g) 2 A(g). The following pictures represent two possible initial states and the equilibrium state of the systenm Drag the terms on the left to the appropriate blanks on the right to complete the sentences Reset Help more This reaction involves bond breaking, so it endothermic is an process. For an process H is Initial state 1 Initial state 2 Equilibrium state is not equal to 0 less exothermic Equilibrium state has randomness than initial state 1. AS for this procesS IS IS for this process negative This a spontaneous positive procesS Submit My Answers Give Up

Explanation / Answer

Initial state:

plenty of A2 molecules; low A molecules

then...

PART 1:

this reaciton involves bond breaking.. so it must be an EXOTHERMIC process.

Reclal that bonds contain energy, therefore, breaking bonds will release this as energy

Fo an EXOTHERMICprocess, the dH for the system/process is NEGATIVE, since it loses energy

PART 2.

Equilibrium state has MORE randmness... This is mainly due to the increase of A molecules vs. A2 which are more ordered

dS for this process must be POSITIVE, since chaos increases

PART 3

dG in this process must be NEGATIVE, since it is going from A2 to 2A; in the forward direction

Them, this must be "IS" a spontaneus pocess

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