Acetic anhydride mw=102) and methanol (mw=32) react to form methyl acetate and a

Question

Acetic anhydride mw=102) and methanol (mw=32) react to form methyl acetate and acetic acid. The enthalpy of this reaction is -67.9 KJ/mole. Use a Cp of 2 J/g for the AA and 1.625 J/g for methanol. Assume the heat capacities of the products are the average of the heat capacities of the reactants – Calculate the Enthalpy per gram of batch and adiabatic temperature rise of this process if equimolar quantites are used. – Calculate the Enthalpy per gram of batch and adiabatic temperature rise if the molar ratios are 2 mols of methanol to 1 mole of acetic anhydride

Explanation / Answer

H rx=-67.9 KJ/mole

CpAA=2J/g

CpMetanol=1.625 J/g

We Assume the heat capacities of the products are the average of the heat capacities of the reactants

Question: Calculate the Enthalpy per gram of batch and adiabatic temperature rise of this process if equimolar quantites are used.

n=0, H=E

CH3COOH +CH3OH ------------------> CH3COOCH3 +H2O

Ifthere is equimolar quantities

H rx=-67.9 KJ/mole* ( 1 mol/ 102g)= 0,66 Kj/g Acetic anhydride

H rx=-67.9 KJ/mole* ( 1 mol/ 32g)= 2,12 Kj/g methanol

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