CHEM 1406-221HY Intr x CHEM 1406-221HY-intro x C Chemistry question Che X CHEM 1

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CHEM 1406-221HY Intr x CHEM 1406-221HY-intro x C Chemistry question Che X CHEM 1406-221HY Intro X C pling 238494. Sapling Lea apling Learning CHEM 1406-221 HY Introductory Chemistry I-G Johnson Activities and Due Dates My Assig 4/13/2016 02:00 PM 56.8/100 4/13/2016 o4:50 PM Gradebook Attempts score Print Calculator Periodic Table Question 17 of 20 Calculate either CH30 or COH for the solutions below at 25 °C. a) OH 1.33 x 10 M H,O b) H,0 8.2 x 10-9 M Which of these solutions are basic at 25 °C c) H,0 0.000669 M Previous 3 Give Up & View Solution Check Answer Next D Exit Hint opyright D 2011-2016 Sa Resources Assignment Information Available From: 3/23/2016 06:00 PM 4/13/2016 02:00 PM Due Date: Late submissions: Allowed with 109 of the points possible deducted per day 04/23/2016 02:00 PM Points Possible: 100 Grade Category: Homework Description: Policies: Homework Late You can check your answers. You can view solutions when you complete or give up on any question You have five attempts per question. You lose 5% of the points available to each answer in your question for each incorrect attempt at that For multiple-choice questions, the penalty depends on the number of choices available. O Help With This Topic O Web Help & Videos O Technical Support and Bug Reports

Explanation / Answer

1.

[H3O+] = kw/[OH-]

[H3O+] = (10^-14)/(1.33*10^-7) =7.518796 *10^-8

basic

2.

[OH-] = Kw/[H3O+]

[OH-.] = (10^-14)/(8.21*10^-9) = 0.00000121 = 1.21*10^-6

basic

3.

[H+] = 6.69*10^-4

acidic

[OH-] = 10^-14)/(6.69*10^-4) = 1.49476*10^-11

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