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In which of the following solutions would solid PbBr_2 be expected to be the lea

ID: 969472 • Letter: I

Question

In which of the following solutions would solid PbBr_2 be expected to be the least soluble at 25 degree C 0.1 M CaBr_2 0.1 M NaBr 0.1 M HBr 0.1 M K NO_3 The molar solubility of cerium iodate, Ce(IO_3)_3, in pure water is 1.865 * 10^-3 M. Calculate the solubility product constant for cerium iodate. 2.6 * 10^_14 3.3 * 10^-10 8.6 * 10^-15 3.5 * 10^-18 4.9 * 10^-19 What is the molar solubility of Mg(OH)_2 in a basic solution with a pH of 13.00? K_sp for Mg(OH)_2 is 5.6 * 10^-12. 2.4 * 10^-6 M 1.1 * 10^-4 M 5.6 * 10^-10 M 5.6 * 10^-11 M

Explanation / Answer

23.

least soluble --> those in which Br is high

PbBr2 <--< Pb+2 and 2Br-

avoid then CaBr2, since it will free 2 mol of Br-

24

Ce(IO3)3 <-> Ce+3 + 3IO3-

Ksp = [Ce+3][IO3-]^3

Ksp = (S) (3S)^3 = 27S^4

Ksp = 27*(1.865*10^-3)^4 = 3.2664*10^-10

choose B

3.

[OH-] = 10^-(14-pH) = 10^-(14-13) = 0.1

Ksp = [Mg+2][OH-]^2

5.6*10^-12 = S*(0.1^2)

S = (5.6*10^-12)/((0.1^2))

S = 5.6*!0^-10