Question
Suppose that you are given the following information for this reaction at room temperature:
?G°f for SO2(g) = ?300.19 kJ?/?mol
?G°f for O2(g) = 0.0 kJ?/?mol
?G°f for SO3(g) = ?371.1 kJ?/?mol
Which statement about this reaction is not correct?
The stoichiometry for this reaction affects your calculations for ?G°. To calculate ?G° for the decomposition of one mole of SO3(
g), you use the expression ?G° = (?G°f for O2 + ?G°f for SO2?) ? (?G°f for SO3?). If ?G° is negative, the reaction is spontaneous. The values for ?G°f from the tables are given for one mole of substance. Look at the following reacti on The stoichiometry for this reaction affects vour calculations for AG° To calculate AG° for the decomposition of one mole of S03(g), you use the expression AG° -(AG °f for 02 + AGf for SO2 )-(AG"f for SO3 ) If AG° is negative, the reaction is spontaneous The values for AG°f from the tables are given for one mole of substance. 2503(g) 2SO2(g)+O2(g) Suppose that you are given the following information for this reaction at room temperature: AG"f for SO2(g) =-300.19 kJ /mol AGf for O2(g) = 0.0 kJ /mol AGf for SO3(g) =-371 . 1 kJ / mol Which statement about this reaction is not correct?
Explanation / Answer
The stoichiometry for this reaction affects your calculations for G°. = TRUE
To calculate G° for the decomposition of one mole of SO3(g), you use the expression G° = (G°f for O2 + G°f for SO2) (G°f for SO3). FALSE, you must calculate as PRODUCT - REACTANTS
If G° is negative, the reaction is spontaneous. TRUE
The values for G°f from the tables are given for one mole of substance.TRUE