Part A: A cylinder, with a piston pressing down with a constant pressure, is fil

Question

Part A: A cylinder, with a piston pressing down with a constant pressure, is filled with 2.20 moles of a gas (n1), and it's volume is 42.0 L (V1). If 0.300 mole of gas leak, and the pressure and the moderators remain the same, what is the final volume of the gas inside the cylinder?
Part B: A sample of gas in a cylinder as in the example in Part A has an initial volume of 70.0 L, and you have determined that it contains 2.00 moles of gas. The next day you notice that some of the gas has leaked out. The pressure and temptation remain the same, but the volume has changed to 17.5 L. How many moles of gas (n2) remain in the cylinder?

Explanation / Answer

Part A:

Initial Volume, V1 = 42.0 L

Initial Number of moles of a gas, n1 = 2.20 moles

Final number of moles of a gas, n2 = 2.20 - 0.300 = 1.90 moles

Final volume, V2 = ?

We know that, V1 / n1 = V2 / n2

V2 = V1 x n2 / n1 = ( 42.0 x 1.90) / 2.20 = 36.3 L

So, the final volume, V2 = 36.3 L

Part B :

Intial VOlume, V1 = 70.0 L

Final volume, V2 = 17.5 L

Initial number of moles, n1 = 2.00 moles

Final number of moles, n2 = ?

We know that,

V1 / n1 = V2 / n2

n2 = V2 x n1 / V1 = (17.5 x 2.00) / 70.0 = 0.5 mol

Therefore, final number of moles of a gas = 0.5 mol.

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