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Part A What is the coordination number for each of the following complexes? A) [

ID: 971814 • Letter: P

Question

Part A

What is the coordination number for each of the following complexes?

A) [Fe(gly)2(H2O)2]+

B) [Pb(EDTA)]2

C) [Pt(NH3)4]2+

D) Na[Au(CN)2]

Enter the coordination numbers, in the order that the complexes are listed, as four integers separated by commas (e.g., 1,2,3,4).

Part B

What is the charge on each of the following complex ions?

A) hexaaquachromium(II), [Cr(H2O)6]?

B) tris(carbonato)ferrate(III), [Fe(CO3)3]?

C) diaquatetrabromovanadate(III), [V(H2O)2Br4]?

Express the charges numerically, in the order that the complexes are listed, separated by commas. For a nonzero charge, be sure to include the sign (e.g., +1,-2,+3).

Part C

What is the oxidation number of the central metal ion in each of the following complexes?

A) [NiCl3F]2

B) [Cr(H2O)2(NH3)4]3+

C) Na[Ag(CN)2]

Express the oxidation numbers numerically, in the order that the complexes are listed, separated by commas. For a nonzero oxidation number, be sure to include the sign (e.g., +1,-2,+3).

Explanation / Answer

Part A

A) [Fe(gly)2(H2O)2]+ --------------->coordination number 6

B) [Pb(EDTA)]2 --------------->coordination number 6

C) [Pt(NH3)4]2+ ----------------->coordination number 4

D) Na[Au(CN)2] ---------------->coordination number 2

answe (6,6,4,2)

Part B

A) hexaaquachromium(II), [Cr(H2O)6]? --------------> +3

B) tris(carbonato)ferrate(III), [Fe(CO3)3] --------------> -3

C) diaquatetrabromovanadate(III), [V(H2O)2Br4]? --------------> -1

answer (+3 , -3 , -1)

Part C

A) [NiCl3F]2 -------------------> +2

B) [Cr(H2O)2(NH3)4]3+ --------------> +3

C) Na[Ag(CN)2] ----------------> +1

answer : (+2 , +3 , +1)

explanation"

for part A)

the number of lignads around central atom or ion called coordination number . suppose C) [Pt(NH3)4]2+   there are 4 NH3 ligands are present , so its coordination number is 4

part B)

for example charge calculations :

[Fe(CO3)3] = x + 3 x -2

                    = x -6

Fe maxium oxidation state is +3 so if you put -3 on square bracket we get +3

part C)

A) [NiCl3F]2

let Ni oxidation state = m

m + 3 x -1 + 1 x -1 = -2

x -4 = -2

x = +2