What is the limiting reactant of camphor to isoborneol and percent yield? Mass o

Question

What is the limiting reactant of camphor to isoborneol and percent yield?
Mass of camphor: 0.072g Molar Mass of camphor: 152.23 g/mol Molar Mass of isoborneol: 154.25 g/mol Mass recovered: 0.71g What is the limiting reactant of camphor to isoborneol and percent yield?
Mass of camphor: 0.072g Molar Mass of camphor: 152.23 g/mol Molar Mass of isoborneol: 154.25 g/mol Mass recovered: 0.71g
Mass of camphor: 0.072g Molar Mass of camphor: 152.23 g/mol Molar Mass of isoborneol: 154.25 g/mol Mass recovered: 0.71g

Explanation / Answer

The limiting reagent in the reduction of camphor to isoborneol is camphor.

moles of camphor = 0.072 g/152.23 g/mol = 4.73 x 10^-4 mols

1 mole of camphor gives 1 mole of isoborneol product

So theoretical yield of isoborneol = 4.73 x 10^-4 mol x 154.25 g/mol = 0.073 g

Actual yield = 0.071 [I think the decmal place is misplaced above]

percent yield = (0.071/0.073) x 100 = 97.26%

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