In the Bronsted-Lowry model an acid is a proton acceptor.an acid is a proton don

Question

In the Bronsted-Lowry model an acid is a proton acceptor.an acid is a proton donor. an acid is an electron pair acceptor. an acid is an electron pair donor. an acid is any substance which contains hydrogen. Which of the following are acid-base reactions according to the Bronsted-Lowry model NM_3(aq) + H_20 right arrow NH_4(aq) + OH-(aq) F-(aq) + H_2O right arrow HF(aq) + OH-(aq) H_2PO_(aq) + OH-(aq) Answers a and c are acid-base reactions. Answers a, b, and c are acid-base reactions. If the H+ concentration in a certain tap-water sample is 4.0 x I0 ^-7 M, what is the OH- concentration (Kw = 1.0 times 10^-14) 2.5 x 10^20M 4.0 times 10 ^-21 M 4.0 times 10^7 M 2.5 times I0 ^-8 M 4.0 times 10 ^-7 M What is the conjugate acid of water H_2O OH- O_2- H_3O+ H+ The conjugate base of a weak acid is a(n) electrolyte weak base weak acid rong acid equilibrium mixture. The pH of 0.350 M benzoic acid, HC_7H_5O_2, is 2.32. What is the pKa for this acid 4.18 2.32 1.79 1.38 0.350 The pH of 0.750 M sodium hypochlorite, NaCIO, is 10.72. What is the pKb for this base 8.04 21.31 6.44 10.72 7.22

Explanation / Answer

1. In the Bronsted-Lowry model,

b. an acid is a proton donor

2. Of the given the Bronsted-Lowry acid base reactions are.

(c) Answers a, b and c are acid-base reactions.

3. If [H+] = 4 x 10^-7 M, [OH-] = 1 x 10^-14/4 x 10^-7,

(d) = 2.5 x 10^-8 M

4. Conjugate acid of water is,

(d) H3O+

5. Conjugate base of a weak acid is in a,

(e) equilibrium mixture.

6. The pH of 0.35 M benzoic acid, pH 2.32, than pKa would be.

(a) 4.18

pH = -log[H+] = 2.32

[H+] = 4.79 x 10^-3 M

Ka = (4.79 x 10^-3)^2/0.35 = 6.55 x 10^-5 M

pKa = -logKa = 4.18

7. The pH of 0.750 M NaClO2 is 10.72. pKb would be,

(c) 6.44

pH = -log[H+] = 10.72

[H+] = 1.905 x 10^-11 M

[OH-] = 1 x 10^-14/1.905 x 10^-11 = 5.25 x 10^-4 M

Kb = (5.25 x 10^-4)^2/0.75 = 3.67 x 10^-7 M

pKb = 6.44

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