Consider the reaction S(s,rhombic) + 2CO(g)SO2(g) + 2C(s,graphite) for which 11°

Question

Consider the reaction S(s,rhombic) + 2CO(g)SO2(g) + 2C(s,graphite) for which 11°-75.80 kJ and S=-167.6 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 1.710 moles of S(s,rhombic) react under standard conditio at 298.15 K ASuniverse = J/K (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored choose 'reactant favored'. enthalpy entropy both Submit Answer om Delta So Universe Calculation: This is group atte

Explanation / Answer

1. S universe = Ssyst + Ssurr

Suniver = Ssyst + Q/T = Ssyst - Hrnx/T

Suniver = -167.6*1.71 - (1.71)*(75.80*1000)/298

Suniv = -721.555 J/K

2.

this reaction favours reactants, since this is not spotnaous

3.

G = H - TS

this is entropy driven, since this is the highest factor present

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