Please help I don\'t understand these at all:( How much 0.100 M NaOH (in mL) is
ID: 991073 • Letter: P
Question
Please help I don't understand these at all:(
How much 0.100 M NaOH (in mL) is required to neutralize 8.00 mL of the 0.100 M acids? Number Drag and drop the graph that demonstrates the point calculated to the right into the box below. e required to neutralize 8.00 mL of 0.100 M HCl- mL Number Base required to neutralize 8.00 mL of0.100 M HC2HO= mL This volume of base and its corresponding pH is known as thel r A good indicator will have a(n) Select answer pH pH 2 Agood indicator will have an) Select ansar close to this volume and pH. Select answer Base Volume Base Volume pH pH Base Volume Base VolumeExplanation / Answer
1)
volume of acid = 8 mL
molarity = 0.1 M
molarity of base = 0.1 M
M1 V1 = M2 V2
0.1 x 8 = 0.1 x V2
base required to neutralize HCl = 8.00 mL
2)
base required to neutralize HC2H3O2 = 8.00 mL
3)
pH at equivalence point
4)
for HCl graph 2.
for HC2H3O2 graph 1