The first you need to do with the general unknown is to preeipitate the chloride
ID: 993983 • Letter: T
Question
The first you need to do with the general unknown is to preeipitate the chlorides or Ag+, life. and Pb^+2. We do this to a mixture of all the possible ions by adding 3 drops Of the I ICI solution. Do you think that 3 drops will be enough to have every silver, mercury, ami lead ion present join with a Cl and precipitate? explain. If you did no even a tiny bit of doudincss with three drops of HCl which would you do not have any silver or but is present. you do not have any of the group I ions present. You did not add enough HCl.Explanation / Answer
QUESTION 1
3 drops of HCl would be sufficient to precipitate a considerable amount of Group I cations, as the experiment usually use a concentrated HCl solution, (about 6M HCl). The solubility of silver, lead and mercury chlorides are very less, thus they will readily precipitate. However, some might remain in solution, but it doesn't affect the experiment as this is a qualitative analysis. If, in case, high volumes of HCl is used, the cations form soluable complexes, and do not precipitate.