Another type of non-simple inheritance is caused by codominance. In this scenari
ID: 99513 • Letter: A
Question
Another type of non-simple inheritance is caused by codominance. In this scenario two alleles of a gene are both expressed in a heterozygote. An example of this is human blood. There are three alleles A, B and o (so this trait also displays non-simple multiple allelism). IA and IB are codominant over allele io meaning a person with: i. Phenotype A blood can have the genotypes = IA IA or IA io ii Phenotype B blood can have genotypes = IB IB or IB io iii. Phenotype AB blood expresses both alleles and has genotype = IA IB (CODOMINANCE) iv. Phenotype O blood has the genotype = io io Assume there is a mix up in the hospital and a single baby potentially belongs to either of two sets of parents. The baby has type o blood. i. Possible parent set 1 = Female IA io blood Male IB io blood ii. Possible parent set 2 = Female io io blood Male IA IB blood a. Draw a Punnett square for parents set #1. What fraction of their offspring will have type AB blood? b. Draw a Punnett square for parents set #2. what fraction of their offspring will have type A blood? c. Which set of parents does the baby with type O blood belong to?Explanation / Answer
a.)Punnett square for parent set 1:
Fraction of offspring with type AB blood=
Offspring with type AB blood÷ total number of offsprings
= 1/4
b.) Punnett square for parent set 2:
Fraction of offspring with type A blood
= number of offsprings with type A blood÷ total number of offsprings = 2/4 = 1/2
c.) Since one offspring with type iOiO blood group is in punnett square 1 and not 2. So, baby with type O blood belongs to 1st set of parents.