On a sheet of paper, write the answer to each question. Use this balanced equati
ID: 999480 • Letter: O
Question
On a sheet of paper, write the answer to each question. Use this balanced equation: 2Al(OH)_3 H_2SO_4 rightarrow Al_2(SO_4)_3 6H_2O You want to convert moles of A1(OH)_3 to moles of H_2SO_4. What mole ratio would you use? If 4.21 mol of A1(0H)_3 reacts, how many moles of H_2SO_4 react? You want to convert moles of H_2SO_4 to moles of H_2O. What mole ratio would you use? If 1.6 mol of H_2SO_4 reacts with excess Al(OH)_3. how many moles of H_2O are produced? You want to convert moles of H_2O to moles ot Al_2(SO_4), What mole ratio would you use? If 3.0 mol of H_2O forms, how many moles of Al_2(SO_4)_3 form? Critical Thinking On a sheet of paper, write the answer to each question. Aluminum and oxygen react to form 1 mol of Al_2O_3 Before you can find out how many moles of oxygen reacted, what do you need to do? How are coefficients in a balanced equation related to mole ratios? The unbalanced equation for a reaction is Na_2O + H_2O rightarrow NaOH. Write two mole ratios comparing moles of NaOH and moles of Na_2O. Circle one of the ratios you wrote for question 9. Then Write.stoichiometry problem that would use it.Explanation / Answer
Reaction:
2Al(OH)3 + 3H2SO4 -> Al2(SO4)3 + 6H2O
1. To convert moles of aluminum hydroxide to moles of sulfuric acid, we use a 3:2 ratio, 3 moles of acid per 2 moles of hydroxide.
2. 4.21 moles of hydroxide * (3 moles of acid / 2 moles of hydroxide) = 6.315 moles of acid
3. We use a 6:3 ratio, 6 moles of water pero 3 moles of acid. We can say that we'll get double moles of water per mole of acid.
4. We'll get 1.6 * 2 = 3.2 moles of water.
5. We use a 1:6 ratio, so we can say we'll get a sixth of a mole of aluminum sulfate per mole of water.
6. 3 moles of water * (1 mol sulfate / 6 moles of water) = 0.5 moles of sulfate.
7. We first need to determine the reaction and stoichiometry of reaction.
8. With coefficients we can determine the ratio of every product and reactant on the equation.
9. Balanced reaction:
Na2O + H2O -> 2NaOH
NaOH/Water ratio is Double moles of NaOH per mole of water
Na2O/NaOH ratio is half moles of sodium oxide per mole of NaOH
10. If we have 10 moles of NaOH, and we want moles of water, we'll get half moles, so we'll get 5 moles of water.