Methanol has the formula CH3OH and can be produced by the reaction of carbon mon
ID: 1010446 • Letter: M
Question
Methanol has the formula CH3OH and can be produced by the reaction of carbon monoxide with hydrogen gas.
Using the above chemical reaction, determine how each of the following actions would affect the equilibrium of the system.
a. heating the mixture _____________________________________
b. adding an excess of carbon monoxide _____________________________________
c. removing the methanol as it is formed _____________________________________
d. adding a substance that reacts with carbon monoxide __________________________
Explanation / Answer
The reaction is CO+2H2---------> CH3OH
a) The reactino is exothermic in the forward direction and according to Lechatlier principle, when the temperature is increased, that is heating the mixture takes the reaction to endothermic reaction. So less productiion of CH3OH at equilibrium
b)
Kc= equilibbrium constant = [CH3OH] / [CO] [H2]2
when excess [CO] is added, the KC increases to keep KC constant [CH3OH] should increase or [H2] should decrease so as to keep Kc constant. So more methanol is formed at equilibrium
c.As methanol is removed as it is formed, Kc decreases and hence [CH3OH] and [H2] also decereased. Hence more methanol is formed at equilibrium
d. when another substance is added that reacts with CO, Co in the denominator decreases. Hence to keep KC consntat [CH3OH] decreases. Hence less CH3OH at equilibrium.