Methanol (CH_3OH) is manufactured by the reaction of carbon monoxide with hydrog

Question

Methanol (CH_3OH) is manufactured by the reaction of carbon monoxide with hydrogen in the presence of a ZnO/Cr2O3 catalyst CO(g) + 2H_2(g) CH_3OH(g), Delta H_0 = -91 kJ Does the amount of methanol increase, decrease, or remain the same when an equilibrium mixture of reactants and products is subjected to the following changes? (a) The temperature is increased; increase, decrease, remain the same (b) the volume is decreased; increase, decrease, remain the same (c) He is added; increase, decrease, remain the same (d) CO is added; increase, decrease, remain the same (e) the catalyst is removed. increase, decrease, remain the same

Explanation / Answer

a)
incraesing temperature favours endothermic reaction
But forward reaction is exothermic.
So reaction will move left
Answer: decrease

b)
decreasing volume move equilibrium to side containing lesser gases
reaction will move right
Answer: increase

c)
adding gas will increase pressure. So it will move equilibrium to side containing lesser gases
reaction will move right
Answer: increase

d)
adding reactant shift reaction to right
Answer: increase

e)
removing catalyst will not effect equilibrium
Answer: remain the same

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

---