In the reaction, 2 H_2O_2 rightarrow 2 H_2O + O_2, what is the number of moles o

Question

In the reaction, 2 H_2O_2 rightarrow 2 H_2O + O_2, what is the number of moles of O_2 produced by the decomposition of 32g of hydrogen peroxide, H_2O_2? 34 0.470 0.941 1.88 In the above questions #5, what is the estimated percent yield if you isolated only 8g of O_2? 53% 58% 60% 64% In the reaction, 2 Al + 3 Cl_2 rightarrow Al_2Cl_6, If you mix 5.40 g of Al with 8.10g of Cl_2, What mass of Al_2Cl_6 can form? 8.1g 9.6g 10.1g 11.1g In the reaction, 2 Al + 6 HCl rightarrow 2 AlCl_3 + 3 H_2, how many grams of HCl are required to completely react with 25.0g of aluminum? 22.6 g 102 g 248 g 105 g

Explanation / Answer

5)

Molar mass of H2O2 = 34 g/mol

moles of H2O2 = mass/molar mass

= 32/34

= 0.9412 mol

2 mol of H2O2 gives 1 mol of O2

moles of O2 formed = 0.9412/2 = 0.4706 mol

Answer b

6)

Molar Mass of O2 = 32 g/mol

mass of O2 formed = number of moles * molar mass

= 0.4706 * 32

=15.06 g

actual yield = 8 g

percent = 8*100/15.06

= 53%

Answer: a

I am allowed to answer only 1 question at a time

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