The combustion of a mol of an unidentified carbohydrate yields 6 mol CO2 and 6 m
ID: 1012325 • Letter: T
Question
The combustion of a mol of an unidentified carbohydrate yields 6 mol CO2 and 6 mol H2O.You want to determine the identity of the carbohydrate from Question 1. Suggest a test that would enable you to do so and discuss how the suggested method will help determine with certainty the identity of the carbohydrate.
Hint: Remember how you learned that the Benedict test can be used to determine if a sugar is reducing or non-reducing? This requires you to propose logical steps you would take to determine exactly what the carbohydrate from Q1 is, knowing its molecular formula from part a of Q1).
The combustion of a mol of an unidentified carbohydrate yields 6 mol CO2 and 6 mol H2O.
You want to determine the identity of the carbohydrate from Question 1. Suggest a test that would enable you to do so and discuss how the suggested method will help determine with certainty the identity of the carbohydrate.
Hint: Remember how you learned that the Benedict test can be used to determine if a sugar is reducing or non-reducing? This requires you to propose logical steps you would take to determine exactly what the carbohydrate from Q1 is, knowing its molecular formula from part a of Q1).
The combustion of a mol of an unidentified carbohydrate yields 6 mol CO2 and 6 mol H2O.
Hint: Remember how you learned that the Benedict test can be used to determine if a sugar is reducing or non-reducing? This requires you to propose logical steps you would take to determine exactly what the carbohydrate from Q1 is, knowing its molecular formula from part a of Q1).
Explanation / Answer
Carbohydrate -----> 6 CO2 + 6 H2O
form the above equation there are 6 carbons and 12 hydrogens in the carbohydrate.
so the molecular formula maybe C6H12O6. Since it is general formula of glucose and fructose and both are the carbohydrates. these are also give possitive test with benedict's solution.
The above two carbohydrates are reducable sugars.