Carbon dioxide, which is recognized as the major contributor to global warming a
ID: 1018833 • Letter: C
Question
Carbon dioxide, which is recognized as the major contributor to global warming as a "greenhouse gas," is formed when fossil fuels are combusted, as in electrical power plants fueled by coal, oil, or natural gas. One potential way to reduce the amount of CO2 added to the atmosphere is to store it as a compressed gas in underground formations. Consider a 1000-megawatt coal-fired power plant that produces about 7×106 tons of CO2 per year.
Part A
Assuming ideal gas behavior, 1.00 atm, and 37 C, calculate the volume of CO2 produced by this power plant.
Express your answer using one significant figure.
2•108
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Part B
If the CO2 is stored underground as a liquid at 10 C and 120 atm and a density of 1.2 g/cm3, what volume does it possess?
Express your answer using one significant figure.
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Part C
If it is stored underground as a gas at 34 C and 80 atm , what volume does it occupy?
Express your answer using one significant figure.
Carbon dioxide, which is recognized as the major contributor to global warming as a "greenhouse gas," is formed when fossil fuels are combusted, as in electrical power plants fueled by coal, oil, or natural gas. One potential way to reduce the amount of CO2 added to the atmosphere is to store it as a compressed gas in underground formations. Consider a 1000-megawatt coal-fired power plant that produces about 7×106 tons of CO2 per year.
Part A
Assuming ideal gas behavior, 1.00 atm, and 37 C, calculate the volume of CO2 produced by this power plant.
Express your answer using one significant figure.
V =2•108
LSubmitMy AnswersGive Up
Incorrect; Try Again; 5 attempts remaining
Part B
If the CO2 is stored underground as a liquid at 10 C and 120 atm and a density of 1.2 g/cm3, what volume does it possess?
Express your answer using one significant figure.
V = LSubmitMy AnswersGive Up
Part C
If it is stored underground as a gas at 34 C and 80 atm , what volume does it occupy?
Express your answer using one significant figure.
V = LExplanation / Answer
Part A ) Volume of CO2 (V) = nRT/P
with,
n = 6,350,293,180,000/44.01 = 1.443 x 10^11 mols
So,
Volume = 1.443 x 10^11 x 0.08205 x (273 + 37)/1 = 3.67 x 10^12 L
Part B ) density of CO2 = 1200 g/L
Volume of CO2 = g/density = 6.35 x 10^12/1200 = 5.29 x 10^9 L
Part C ) Volume of CO2 = nRT/P
= 1.443 x 10^11 x 0.08205 x (273 + 34)/80
= 4.54 x 10^10 L