Part A The rate constant for a certain reaction is k = 9.00×10 ?3 s^(?1) . If th

Question

Part A

The rate constant for a certain reaction is k = 9.00×10?3 s^(?1) . If the initial reactant concentration was 0.800 M, what will the concentration be after 2.00 minutes?

Part B

A zero-order reaction has a constant rate of 2.40×10?4M/s. If after 65.0 seconds the concentration has dropped to 3.00×10?2M, what was the initial concentration?

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Introduction to Integrated Rate Laws Part A The rate constant for a certain reaction is k-9.00x10-3 s-1 . If the initial reactant concentration was 0.800 M, what will the concentration be after 2.00 minutes? Learning Goal: To understand how to use integrated rate laws to solve for concentration, Express your answer with the appropriate units. A car starts at mile marker 145 on a highway and drives at 55 mi/hr in the direction of decreasing marker numbers. What mile marker will the car reach after 2 hours? Value Units This problem can easilv be solved by calculating Figure 1 of 2 Submit Hints My Answers Give Up Review Part zero-order Part B A zero-order reaction has a constant rate of 2.40x10-4 M/s. If after 65.0 seconds the concentration has dropped to 3.00×10-2 M, what was the initial concentration? Express your answer with the appropriate units. Value Units time Submit Hints My Answers Give Up Review Part

Explanation / Answer

A. According to the units of the rate constant in part A, its a first order reaction.

C=C0 e-kt or logC = logC0 -kt/2.303

logC= log 0.8-9×10-3×120/2.303

C=0.2717moldm-3

B. d(C) /dt =-kC

(C) = (C0) -kt

3×10-2=(C0) - 2.4×10-4×65

(C0) =0.0456moldm-3

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