Please show step by step work! Page 6 of 6 Chem2O1 Lab Prectical Misc. Tepics Sh

Question

Please show step by step work! Page 6 of 6 Chem2O1 Lab Prectical Misc. Tepics Show all work re receive credn re) redusced to iroaar) by chremumttr n acidic solution according to the foliowing unbolanced reaior The experiment requines 66.9 g of Fe3. to be completely reduced by 208 of ased on this information, whet is the oxidatien shate of the chromum in the chranium axide oxide preduct? What is the possible chremium oxide preduct? Each cell for the cell below, 9. Use the stendard neduction potentiols to determine The net reaction and standard cell potential contains a 1.00 M solution of the indiceted eation in contact with an electrede of thet meutral metol. Standard Reduction Potential (E) Electron Flow a ee 0447 V 2+ Cr Fe So 2- SO Separator interface Reaction Crcle the correct net reaction from the choices above. ii) what is the E·(potential) for the reaction you have chosen? 10. The standard reduction potential for Zn2 is -0.76 V Calculate the voitage of the following cell at 25 c. Znzn2 (LoM)H(0.010 M)H2910 atm)pt a 058 v b. 041 V 0.94V d. 0.76 V e. 0.64V 138

Explanation / Answer

8. moles of Fe3+ = 66.9 g/55.845 g/mol = 1.20 mols

moles of Cr3+ = 20.8 g/51.996 g/mol = 0.40 mols

the ratio of Fe3+ to Cr3+ being 3 : 1

So the oxidation state for Cr in products is +6

The likely chromium oxide product would be,

e. Cr2O7^2-

9. For the given cell

i) Net reaction ,

(C) 2Cr + 3Fe2+ ---> 2Cr3+ + 3Fe

ii) Eo = -0.447 - (-0.744) = 0.297 V

10. Using Nernst equation,

E = Eo - 0.0592/n logQ

   = 0.76 - 0.0592/2 log(1/(0.01)^2)

   = 0.641 V

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---