Mass of cylinder after evaporation: 215 g Calculate: the volumetric flow rate an
ID: 1024054 • Letter: M
Question
Mass of cylinder after evaporation: 215 g Calculate: the volumetric flow rate and mass flow rate of the suspension the density of the suspension the mass fraction of calcium carbonate (CaCO_3) in the suspension. Perform the following pressure conversions, assuming when necessary chat atmospheric pressure is 1 atm. Unless otherwise stated, the given pressures are absolute 2600 mm Hg to psi 275 ft H_2O to kPa 3.00 atm to N/cm^2 280 cm Hg to dyne/m^2 20 cm Hg of vacuum to atm (absolute) 25.0 psig to mm Hg (gauge) 25.0 psig to mm Hg (absolute) 32.5 mm Hg to mm gauge 35.0 psi to cm of carbon tetrachloride Convert the following:Explanation / Answer
1.
2600 mm Hg to psi
2600 Hg = 50.275704 psi
2.
275 ft H2O to kPa
1 .00 ft H2O = 2.99 kPa
275 ft H2O =821.97 kPa
3.
3.00 atm to N /cm^2
1.00 atm =210.1325 N /cm^2
3. 00 atm = 30.3975 N /cm^2
4
280 cm Hg to dyne / m^2
1.00 mm Hg = 1.333e+7 dyne / m^2
280 cm = 2800 mm
2800 mm Hg = 3.733e+10dyne / m^ 2
5 20 cm Hg of vacume to atm
200 mm Hg of vacume to atm
= 0.26316 Atmospheres (atm)
6.
25.0 psig = 2052.873317 mm Hg gauge
1.00 PSI Gauge = 811.714934 mmHg
7
Psig to mmHg absolute
p(absolute)=p(gauge)+p(atmospheric)
=2052.873317 mm Hg + 760 mm Hg
= 2812.873 mmHg absolute
1.00 PSI Gauge = 811.714934 mmHg