Can please answer the question and graph the following. Thank you Solution conce
ID: 1025181 • Letter: C
Question
Can please answer the question and graph the following.
Thank you
Explanation / Answer
Answer:
since concentration is proportional to absorbance and concentration is related to rate of species A (-dA/dt) as
-dA/dt= K[A]n, n is the order of reaction. K is the rate constant
for n=1, the reaction is 1st order and for 1st order, -dA/dt= K[A], when integrated noting at t=0 , A=[A]0 and t= t, [A]=[A]
lnA= ln[A]0-Kt, so a plot of lnA vs t gives straight line whose slope will be-K for1st order.
for second order, n=2 and the intergrated equation is 1/A= 1/[A]0+Kt, so a plot of 1/A vs t has to be straight line.
Since here concentration of A is measured in terms of Absorbance, 1st order and 2nd order are verfied by drawin either a plot of lnA vs t or 1/A vs t. The generated plots are shown below.
from the plots it can be seen that the plot of lnA( A refers to absorbance which is proportional to concentration) vs t is having high R2 value and gives the best fit. Hence the reaction 1st order. The slope value is -K and gives the rate constant value K=0.035/min