QUESTION 2 If 8.112g of potassium oxalate hydrate is added to a beaker and then

Question

QUESTION 2 If 8.112g of potassium oxalate hydrate is added to a beaker and then 20.0mL of DI water is added to dissolve and then 10.0mL of 1.0 M FeCla is added. Which statement is correct the beaker contains 0.0440 moles of potassium oxalate hydrate and 0.0100 moles of iron(IIl) chloride the beaker contains 0.153 moles of potassium oxalate hydrate and 0.0100 moles of iron(lII) chloride the beaker contains 2.20 moles of potassium oxalate hydrate and 0.012 moles of iron(III) chloride the beaker contains 2.20 moles of potassium oxalate hydrate and 10.0 moles of iron(II) chloride the beaker contains 0.0100 moles of potassium oxalate hydrate and 0.0440 moles of iron(I) chloride

Explanation / Answer

Answer

The beaker contains 0.0440moles of potassium oxalate hydrate and 0.0100 moles of Iron(III)chloride

Explanation

i)Calculating moles of potassium oxalate hydrate

No of moles = mass /molar mass

No of moles of potassium oxalate hydrate = 8.112g/184.23g/mol =

ii) calculating moles of Iron(III)chloride

1.0M = 1mole per Liter of solution

Therefore,

no of moles in 10ml of solution=(1.0/1000)×100 = 0.01 mol

  

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