Show all work for full credit. To standardize your NaOH solution, you titrate 25

Question

Show all work for full credit. To standardize your NaOH solution, you titrate 25.0 mL of 0.0822 M HCI solution, measuring the pH after cach small addition of NaOH. Following is the graph you obtain. The equivalence point occurs where there is a steep rise in pH. 1) 14 What molar quantity of HCl is being titrated? iew Low What molar quantity of NaOH has been added at the equivalence point? e 6 8 10 12 14 16 10 20 22 24 26 28 30 vo lume of Base What volume of NaOH solution has been added at the equivalence point? Expanded view of the equivalence point: what is the concentration of the NaOH solution? 10 22 2324267 Voluse of sase

Explanation / Answer

1)

moles of HCl being titrated = 25 x 0.0822 / 1000

                                          = 2.055 x 10^-3

molar quantity of HCl titrated = 2.06 x 10^-3 mol

2)

At equivalence point :

moles of HCl = moles of NaOH

molar quantity of NaOH at equivalence point = 2.06 x 10^-3 mol

3)

volume of NaOH At equivalence point = 24.0 mL

4)

moles of NaOH = 2.06 x 10^-3 mol

0.024 x M = 2.06 x 10^-3

M = 0.0856

concentration of NaOH = 0.0856 M

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