Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Mapt Sapling Learning The IR (infrared) spectra of two pure compounds (0.020 M c

ID: 102899 • Letter: M

Question

Mapt Sapling Learning The IR (infrared) spectra of two pure compounds (0.020 M compound A in solvent, and 0.020 M compound B in solvent) are shown to the right. The pathlength of the cell is 1.00 cm. Note that the y axis in the spectra is transmittance rather than absorption, so that the wavenumbers at which there is a dip in the curve correspond to absorption peaks 100 90 80 70 2976 cm A mixture of A and B in unknown concentrations gave a percent transmittance of 48.2% at 2976 cm-1 and 36.0% at 3030 cm-1 F 30 20 10 3030 cm- Pure A Pure B 3040 2990 2940 2890 Wavenumber 0.020 MA 0.020 M B 3030 cm-1 | 35.0% 2976 cm-1 | 76.0% What are the concentrations of A and B in the unknown sample? Unknown 36.0% 48.2% Wavenumber (cm- 93.0% 42.0% Number [B] = 110 M A M B

Explanation / Answer

wave number (cm-1)

A

B

unknown

3030

0.456

0.0315

0.444

2976

0.119

0.377

0.317

Absorbance = A = E x b x C

wave number

A

B

3030

E = 23 M-cm-1

1.6 M-1 cm-1

2976

E = 6.0 M-1 cm-1

19 M-1 cm-1

0.444 = 23 x 1 x A + 1.6 x 1 x B

0.444 = 23 A + 1.6 B ----------------------(1)

0.317 = 6 x 1 x A + 19 x 1 x B

0.317 = 6 A + 19 B ---------------------(2)

by solving these two

A = 0.0186 M

B = 0.0108 M

wave number (cm-1)

A

B

unknown

3030

0.456

0.0315

0.444

2976

0.119

0.377

0.317