All those calculation correct b,e, h,j,k,l,m,n ? I need help with the last colum

Question

All those calculation correct b,e, h,j,k,l,m,n ?
I need help with the last column that is in blank please Trial 1 Trial 2 Trial 3 a) Volume of water in can (mL b)Mass of water in can (g) 2000 mL | 2000m1 2000ml 0 Initial Water 200.09 200 0g 200.09 Temperature oc) 20 4 oC 20.3 °C 20.go d) Final Water Temperature (C) e) Temperature Change 100C 990°C 00 22,539q .3169 22. 5359 22.5460 22.622 )Mass of nut residue (g) 0400340a 0 O830 f) Mass of empty beaker (g) D) Mas of beaker with 22539g 22. 339 nut (g) b) Initial mass of nut (g) 209a i) Mass of beaker with nut residue (g) 22535 2 360 k) Mass of nut lost by0.g0.34+0 0. burning (g) 1) Total energy released m) Total energy released (keal n) Energy released per g of nut burned (kcal/g) Mean kcal/g | Standard | Deviation S | % Accepted | % Error Deviation value kcal/g 36 .2 2 62

Explanation / Answer

% Error is calculated as (Standard Error/Theoretical Yield)*100.

Standard error is calculated from standard deviation by dividing the standard deviation by the root of the number of readings taken which in this case arrives as 12.5285.

Now the accepted value can be found as mean +/- standard error which gives 48.7285 or 23.6175 as a possible accepted value giving the percentage error as 25.71% or 53.04%.

Unless the accepted value is given, the precise % error calculation however is only a hypothetical guess from the obtained results.

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