Please explain how to solve thanks A chemical engineer is studying the two react

Question

Please explain how to solve thanks A chemical engineer is studying the two reactions shown in the table below. In each case, he fills a reaction vessel with some mixture of the reactants and products at a constant temperature o second reaction. The results of his measurements are shown in the table. Complete the table. That is, calculate G for the first reaction and S for the second. (Round your answer to zero decimal places.) Then decide whether, spontaneous because the system is at equilibrium. Then, he measures the reaction enthalpy Afand reaction entropy A,S of the first reaction, and the reaction enthalpy AH and reaction free energy AG of the the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction is AS5372 4Fe(s) + 30,(x) 2Fe:0,0) Which is apontaneous? this reaction the reverve reaction O neither All 2220. kJ K. Which is spontaneous? this reaction the reverse reaction neither

Explanation / Answer

For the first reaction

4Fe(s) + 3O2(g) -------- 2Fe2O3(s)

Delta H= -1648 kJ

Delta S = -5372 J/K

Temperature = 33C = 33 + 273 = 306K

Delta G = Delta H - T * Delta S

=> -1648 kJ + (5372)/1000 * 306 kJ

=> -4.168 kJ

Since the Delta G is negative, hence this reaction is spontaneous, correct answer will be Option A

For the second reaction

3CO2(g) + 4H2O(g) ------ C3H8(g) + 5O2(g)

Delta H= 2220kJ

Delta G = 22 kJ

Temperature = 33C = 33 + 273 = 306K

Delta G = Delta H - T * Delta S

22 kJ = 2220kJ - T * Delta S

306 * Delta S = 2198

Delta S = 7183. J/K

Since the Delta G is positive, hence this reaction is not spontaneous but the reverse reaction will be spontaneous, correct answer will be Option B

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