I know how to get the oxidation state for sulfur, but I don\'t understand how th

Question

I know how to get the oxidation state for sulfur, but I don't understand how they got -7.33 for x.

eactions and Activity Series Mozilla Firefox /myct/ftemView?assignmentProblemlD-96668379 150% edox Reactions and Activity Series 1of8 rar c What is the oxidation state of an individual sulfur atom in SO42? Express the oxidation state numerically (e.g., +1). nts Periodic Table ant for keeping track uction reactions. Here emember: View Available Hintis) en has an 2. 2 elements on ave +1 and +2 spectively rogen has an 1. n have more than e. In such cases nents in the oxidation states rmine the Hint 1. Derive the equation to solve for the oxidation state of sulfur Since SO4 has an overall charge of -2, the following equation applies where a is the oxidation state of an individual sulfur atom and y is the oxidation state of an individual oxygen atom. How can this equation be rearranged to solve for r? Express your answer in terms of y. the element that 847 AM 0 9 Shilt

Explanation / Answer

Oxidation state of individul sulfur in sulfate (SO42-)

The net charge of sulfate = -2

The valency of oxygen is -2 be y

Let x is oxidation state of S

x+4y = -2

x+4(-2) = -2

x-8 = -2

x = -2+8 = +6

So the oxidation state of Sulfur is +6

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