For the next 6 question refer to the chemical reaction below. 6. (5 points) Writ

Question

For the next 6 question refer to the chemical reaction below. 6. (5 points) Write the balanced chemical equation. 601+3 7. (5 points) For every mole of AI(NO,)s, how many moles of Al2(SO)s are produced? For every mole of H2SOs, how many moles of Al2(SO4)s are produced? For every mole of AI(NOs)s, how many moles of HNOs are produced? For every mole of H2SO4, how many moles of HNOs are produced? For every mole of H2SO4, how many moles of AlONOs)s are required? 8. If given 29 grams of each reactant, determine the limiting reagent.

Explanation / Answer

Balanced equation:

2 Al(NO3)3 + 3 H2SO4 = Al2(SO4)3 + 6 HNO3

Ans 7

A) from the stoichiometry of the reaction

2 mol of Al(NO3)3 produces = 1 mol of Al2(SO4)3

1 mol of Al(NO3)3 produces = 0.5 mol of Al2(SO4)3

B) 3 mol of H2SO4 produces = 1 mol of Al2(SO4)3

1 mol of H2SO4 produces = 0.333 mol of Al2(SO4)3

C) 2 mol of Al(NO3)3 produces = 6 mol of HNO3

1 mol of Al(NO3)3 produces = 3 mol of HNO3

D) 3 mol of H2SO4 produces = 6 mol of HNO3

1 mol of H2SO4 produces = 2 mol of HNO3

E) 3 mol of H2SO4 require = 2 mol of Al(NO3)3

1 mol of H2SO4 require = 0.666 mol of Al(NO3)3

Ans 8

Moles of H2SO4 = mass/molecular weight

= 29/98.07 = 0.2957 mol

mol of Al(NO3)3 = 29/213 = 0.1362 mol

1 mol of H2SO4 require = 0.666 mol of Al(NO3)3

0.2957 mol of H2SO4 require = 0.666*0.2957 = 0.1969 mol of Al(NO3)3

But we have only 0.1362 mol which is less than the required 0.1969 mol

Therefore Al(NO3)3 is limiting reactant

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