Chase Elderflower Liqueur contains 20 % (v/v) ethanol, Unfortified wine contains
ID: 1032735 • Letter: C
Question
Chase Elderflower Liqueur contains 20 % (v/v) ethanol, Unfortified wine contains 14 % (v/v) ethanol, and Victoria Bitter contains 4.9 % (v/v) ethanol. a) Calculate the concentration of ethanol in the 3 separate beverages. .Give the concentrations in g/L Give the concentrations as molarities b) Determine the total mass (g) of ethanol in each of the following3 beverages. 500 mL bottle of Chase Elderflower Liqueur 750 mL bottle of Unfortified wine 6 pack (6 x 375 mL) of Victoria Bitter Which of these drinks, as detailed above, contains the highest amount (in g) of ethanol?Explanation / Answer
Ans. #a. I. Amount of ethanol in CEL = 20 % (v/v) = 20 mL EtOH / 100 mL solution
A 20% (v/v) means there is 20 mL of solute per 100 mL of the solution.
Now,
Volume of EtOH in 1.0 L CEL = (20 mL EtOH / 100 mL soln.) x 1000.0 mL
= 200 mL
Mass of EtOH in 1.0 L CEL = Vol x Density = 200 mL x (0.79 g mL-1) = 158 g
So, So, [EtOH], g/ L = 158 g/ L
Moles of EtOH in 1.0 L CEL = Mass / MW = 158 g / 46.07 g mol-1 = 3.43 mol
So, [EtOH], molarity = Moles / Vol in L = 3.43 mol / 1.0 L = 3.43 M
#II. Amount of ethanol in UnfW = 14 % (v/v) = 14 mL EtOH / 100 mL solution
Now,
Volume of EtOH in 1.0 L UnfW = (14 mL EtOH / 100 mL soln.) x 1000.0 mL
= 140 mL
Mass of EtOH in 1.0 L UnfW = Vol x Density = 140 mL x (0.79 g mL-1) = 110.6 g
So, So, [EtOH], g/ L = 110.6 g/ L
Moles of EtOH in 1.0 L UnfW = Mass / MW = 110.6 g / 46.07 g mol-1 = 2.40 mol
So, [EtOH], molarity = Moles / Vol in L = 2.40 mol / 1.0 L = 2.40 M
#III. Amount of ethanol in UB = 4.9 % (v/v) = 4.9 mL EtOH / 100 mL solution
Now,
Volume of EtOH in 1.0 L VB = (4.9 mL EtOH / 100 mL soln.) x 1000.0 mL = 49 mL
Mass of EtOH in 1.0 L VB = Vol x Density = 49 mL x (0.79 g mL-1) = 38.71 g
So, So, [EtOH], g/ L = 38.71 g/ L
Moles of EtOH in 1.0 L VB = Mass / MW = 38.71 g / 46.07 g mol-1 = 0.84 mol
So, [EtOH], molarity = Moles / Vol in L = 0.84 mol / 1.0 L = 0.84 M
#b. #I. Total mass of EtOH in CEL = [EtOH] in g L-1 x Vol in liters
= (158 g/ L) x 0.500 L = 79.0 g
#II. Total mass of EtOH in UnfW = (110.6 g/ L) x 0.750 L = 82.95 g
#III. Total mass of EtOH in VB = (38.71 g/ L) x ( 6 x 0.375 L) = 87.09 g
Therefore, VB (Victoria Bitter) has highest amount of EtOH.