Please help, I keep getting it wrong. Thank you. Calculate the standard enthalpy

Question

Please help, I keep getting it wrong. Thank you. Calculate the standard enthalpy change for the following reaction at 25 C. Standard enthalpy of formation values can be fo [Macmilla d. Skyline College.( HEM × D Thermodynamics. Chempel + /mod/ibis/view.php?id-4802761 Jump to... K? stion 3 of 11 Incorrect IncomectIncorrectIncorrect Incorrect Map eneral Chemistry 4th Edition University Science Books presented by Sapling Leaming Consider an ideal gas enclosed in a 1.00 L container at an internal pressure of 16.0 atm Calculate the work, w, if the gas expands against a constant external pressure of 1.00 atm to a final volume of 16.0L Number w= 11-1519.8 Now calculate the work done if this process is carried out in two ste Step 1: Let the gas expand against a constant external Step 2: From the end point of step 1, let the gas expand to 16.0 L against a constant external pressure of 1.00 atm. re of 3.20 atm to a volume of 5.00 L Number w= 1-15 lip

Explanation / Answer

A. Work = -Pexternal*Volume change
-1 atm * (16 - 1)L = -15 atm-L.
1 atm-L = 101.324999971 J
So, -15 * 101.32 = -1519.8 J

B.

Calculate each step individually then sum the answers.
For step 1)
-3.2 atm * (5-1)L = -12.8 atm-L
step 2)
-1 atm * (16-5)L = -11 atm-L

Thus total work = -23.8 atm-L
convert to joules, 1 atm-L = 101.324999971 J
W= -2411.535 J

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