Can you please help me with this question College SE-CHEM 1412-Spring18-CONIGLIO

Question

Can you please help me with this question

College SE-CHEM 1412-Spring18-CONIGLIOActivities and Due Dates HW 16 4/12/2018 11:00 PM 4 872/100 4/4/2018 06:12 PM Print Calculator Periodic Table Question 21 of 26 Sapling Learning For a particular reaction, NH- -238.4 kJ/mol and AS -80.0 J/(mol K) Calculate AG for this reaction at 298 K. Number kJ/ mol What can be said about the spontaneity of the reaction at 298 K? O O O The system is spontaneous as written The system is spontaneous in the reverse direction. The system is at equilibrium. 0 Previous ? Give Up & View Solution Check Answe Hint about us careers pri APR 3 4.

Explanation / Answer

we have the relation as,

dG rxn = dH rxn - T * dS rxn

dH rxn is given as -238.4 * 10^3 J/mol

dS rxn = -80 J/mol. K

T = temperature = 298 K

then,

dG rxn = (-238.4 * 10^3) - 298*(-80)

dG rxn = -214560 J

dG rxn = -214.56 kJ

since fro spontaneous process dG < 0 i.e, the value of dG = -ve

so the value of the given reaction is dG = -214.56 kJ hence it is spontaneous reaction.

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---