If you were going to graphically determine the enthalpy The equilibrium constant

Question

If you were going to graphically determine the enthalpy The equilibrium constant, K, of a certain first order reaction was measured at two temperatures, T r, for this reaction, what points would you plot? The data is shown in this table Number Number T(K) K 325 575 To avoid rounding errors, use three significant figures in the x values and four significant figures in the y values. point 1: 3.94 5.10 Number Number point 2: Determine the rise, run, and slope of the line formed by these points rise run slope Number Number Number What is the standard enthalpy of this reaction? Number J/mol

Explanation / Answer

We need to plot lnK on y axis and 1/T on x axis
K = 3.94
ln K = ln (3.94) = 1.37118
T = 325.0
1/T = 0.00308


point 1 is:
x = 0.00308
y = 1.37118


K = 5.1
ln K = ln (5.1) = 1.62924
T = 575.0
1/T = 0.00174


point 2 is:
x = 0.00174
y = 1.62924


----------------------------------------------------------------------------
rise = (y1-y2) = 1.37118 - 1.62924 = -0.25806
rise = (X1-X2) = 0.00308 - 0.00174 = 0.00134
slope = rise/run
= -0.25806/0.00134
= -192.89971
----------------------------------------------------------------------------
use
slope = - delta H/R
= -192.89971 = -delta H/8.314
delta H = 1604 J/mol

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