CHAPTER9 o Figure 9.14 K10 of 20> Constants 1 Periodic Table Part A (Figure 1) F
ID: 1043221 • Letter: C
Question
CHAPTER9 o Figure 9.14 K10 of 20> Constants 1 Periodic Table Part A (Figure 1) Formation of the H2 molecule as atomic orbitals overlap. On the left part of the curve the potential energy rises above zero. What causes this to As the internuclear distance attraction becomes a dominant component of the potential energy As the internuclear distance attraction becomes a dominant component of the potential energy As the internuclear distance repulsion becomes a dominant component of the potential energy As the internuclear distance repulsion becomes a dominant igure 1 of 1 component of the potential energy Sub x Incorrect; Try Again; 5 attempts remaining Potential energy decreases with increasing orbital overlap -436 mportant ide Feedback Next > 0.74 A H--H distance Balance between attractive and repulsive forcesExplanation / Answer
as internuclear distances decrease attraction dominant on repulsion so energy release and cause decrease in potential energy. but there is a limit (in Question upto 0.74 A*) . After that repulsion dominant on attraction and gain of potential energy takes place .
or nuclear repulsion are greater than electronic repulsion when potential energy starts increasing. so main reason between C option or D option is C option
so the answer is C / third part