Please help, I got an answer 86.2 is incorrect. Calculate the temperature (in °C

Question

Please help, I got an answer 86.2 is incorrect.

Calculate the temperature (in °C) at which cyclohexane boils at a mountain top research facility where the atmospheric pressure is 650.0 torr This type of calculation is very sensitive to precision. Carry at least 5 decimal places through your calculations and then round your answer to one decimal place at the end. Also use the conversion that K=°C+273.15 boiling point Solvent formula MW vap kJ/mol C.H.O 58.08 CHN 41.05 78.11 153.8 119.4 84.16 C,H.o 74.12 56.1 81.7 80.1 76.8 61.2 80.7 34.5 acetone acetonitrile benzene carbon tetrachloride chloroform cyclohexane diethyl ether dimethyl formamid (DMF) C3HNO 73.09153.0 dimethyl sulfoxide (DMSO) C2HGOS 78.13189.0 ethanol ethylene glycol glycerin heptane methanol methylene chloride 2-propanol pyridine tetrahydrofuran (THF) toluene water 33.23 30.72 29.82 29.24 29.97 26.52 46.7 52.9 38.56 C.H CCI CHCI C.H 4 6 12 4 10 C.H O46.07 C.H.O 62.07 C2H2O, 92.09 78.5 195.0 290.0 26 2 91.7 C,H16100.298.031.77 35.21 28.06 3 8 3 32.04 64.6 39.8 82.4 115.2 65.0 CHAO CHACI 22 84.93 C.H.O 88.15 35.09 29.81 C,Hg92.14110.6 33.18 C.H N79.1 C,H O 72.11 18.02 100.0 40.67 2

Explanation / Answer

P1 = 760 torr (This is pressure at normal boiling point)

P2 = 650 torr

Hvap = 29.97 KJ/mol

= 29970.0 J/mol

we have below equation to be used:

ln(P2/P1) = (Hvap/R)*(1/T1 - 1/T2)

ln(650/760) = (29970.0/8.314)*(1/353.85 - 1/T2)

-0.15635 = 3604.7631*(1/353.85 - 1/T2)

T2 = 348.5 K

= (348.5-273.15) oC

= 75.4 oC

Answer: 75.4 oC

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