Post Lecture Homework Chapter 11 oblem 11.78- Enhanced-with Feedback 22 of 22 P-

Question

Post Lecture Homework Chapter 11 oblem 11.78- Enhanced-with Feedback 22 of 22 P- 761 mmHg Constants 1 Periodic Table You may want to reference Pages 349-353) Section 11.9 while completing this problem Correct When Zn reacts with HCl solution, the products are H2 gas and ZnCl Since a sample collected over water is a mixture of the gas desired (H2 here) and water vapor, the total pressure is the sum of the pressures of both gases. By subtracting the pr the water vapor (14 mmHg) from 775 mmHg, the pressure of the H2 gas can be calculated essure contributed by Zn(s) + HCl(aq)?H2(g) + ZnQ2(a) A volume of 443 ml of H2 gas is collected over water at a total pressure of 775 mmHg and 16 C The vapor pressure of water at 16 Cis 14 mmHg Part B How many moles of H2 gas were produced in the reaction? Express your answer with the appropriate units. nValue Units Submit

Explanation / Answer

partial pressure is defined as the pressure exerted by the gas if it alone occupies the entire volume

partial pressure of hydrogen= total pressure- saturation pressure of water at 16 deg.c= 775-14= 761 mm Hg

since 760 mm Hg= 1 atm, 761 mm Hg= 761/760 atm = 1.00 atm, T= 16 deg.c= 16+273= 289K, V= 443ml, 1000ml= 1L

V= 443/1000 L=0.443L, R= gas constant= 0.0821L.atm/mole.K

from gas law, n= moles of hydrogen= PV/RT =1*0.443/(0.0821*289)= 0.019 moles

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