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I need help with these homework problem sets as I have no clue how to engage int

ID: 1047863 • Letter: I

Question

I need help with these homework problem sets as I have no clue how to engage into them!

14. (5pnts) What is the molarity of potassium ion in the following solutions: a. 0.20 M potassium chloride b. 0.15 M potassium chromate c. 0.080 M potassium phosphate 15. (5pnts) How many mL of 6.0 M nitric acid are needed to prepare 100.0 mL of 0.500 M nitric acid? 16. (5pnts) Pure acetic acid, known as glacial acetic acid, is a liquid with a density of 1.049 g/mL. Calculate the molarity of a solution of acetic acid made by dissolving 20.00 mL of glacial acetic acid in enough water to make 250.0 mL of solution. 17. (5pnts) How many milliliters of 0.128 M hydrochloric acid is needed to neutralize 2.87 g of solid magnesium hydroxide? 18. (5pnts) If 25.8 mL of a silver nitrate solution is needed to precipitate all the chloride ions in a 785- mg sample of KCI (forming silver chloride), what is the molarity of the AgNO3 solution?

Explanation / Answer

a.   KCl ---------> K+ + Cl-

    0.2M             0.2M

molarity of K+ is 0.2M

b. K2CrO4 --------> 2K+ + CrO42-

   0.15M                 2*0.15M

molarity of K+ is 0.3M

c. K3PO4 ----------> 3K+ + PO43-

     0.08M                   3*0.08M

molarity of K+ is 0.24M

15.   initial                                                         Final

      M1 = 6M                                                 M2 = 0.5M

     V1    =                                                       V2   = 100ml

               M1V1    = M2V2

                V1   = M2V2/M1

                       = 0.5*100/6   = 8.33ml

16.   mass of acetic acid = volume* density

                                         = 20*1.049   = 20.98g

   molarity   = 20.98*1000/60*250    = 1.4M

17.    no of moles of Mg(OH)2 = W/G.M.Wt

                                              = 2.87/58.31 = 0.05moles

Mg(OH)2 + 2HCl ---------> MgCl2 +2H2O

1 mole of Mg(OH)2 react with 2 moles of HCl

0.05 moles of Mg(OH)2 react with = 2*0.05/1 = 0.1mole of HCl

molarity = no of moles/volume in L

0.128      = 0.1/volume in L

volume in L = 0.1/0.128   = 0.78L  

                   = 780ml