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Complete the following table for a selection of foods: Food [H3O+] [OH] pH Acidi

ID: 1051305 • Letter: C

Question

Complete the following table for a selection of foods:
Food   [H3O+]   [OH]   pH   Acidic, basic, or neutral?
Apple juice           3.80  
Soy milk               neutral
Tuna (canned)    6.3×107M          

A) Calculate the [H3O+] of apple juice with pH=3.80 .

Express the molarity to two significant figures.

B) Calculate the [OH] of apple juice with pH=3.80 .

Express the molarity to two significant figures.

C) Calculate the [H3O+] of soy milk.

Express the molarity to two significant figures.

D) Calculate the [OH] of soy milk.

Express the molarity to two significant figures.

E) Calculate the pH of soy milk.

Express the pH to two decimal places.

F) Calculate the [OH] of tuna (canned) with [H3O+] = 6.3×107M .

Express the molarity to two significant figures.

G) Calculate the pH of tuna (canned) with [H3O+] = 6.3×107M .

Express the pH to two decimal places.

Explanation / Answer

A) pH =-log[H3O+]

3.80=-log[H3O+]

-3.80= log[H3O+]

10-3.8 =[H3O+]

[H3O+] =1.58x10-4 M

B) pH + pOH = 14

3.8 + pOH =14

pOH= 10.2

pOH=-log[OH-]

-10.2= log[OH-]

10-10.2 = [OH-]

[OH-] = 6.31x10-11 M

C) If the milk is neutral, its pH is 7.

pH =-log[H3O+]

7=-log[H3O+]

-7= log[H3O+]

10-7 =[H3O+]

[H3O+] =1.00x10-7 M

D) pH + pOH = 14

7 + pOH =14

pOH= 7

pOH=-log[OH-]

-7= log[OH-]

10-7 = [OH-]

[OH-] = 1.00x10-7 M

E) If the milk is neutral, its pH is 7.00.

F) pH =-log[H3O+]

pH =-log 6.3x10-7

pH=6.20

pH + pOH = 14

6.20 + pOH =14

pOH= 7.80

pOH=-log[OH-]

-7.80= log[OH-]

10-7.80 = [OH-]

[OH-] = 1.58x10-8 M

G) pH =-log[H3O+]

pH =-log 6.3x10-7

pH=6.20