Complete the following table for a selection of foods: Food [H3O+] [OH] pH Acidi
ID: 1051305 • Letter: C
Question
Complete the following table for a selection of foods:
Food [H3O+] [OH] pH Acidic, basic, or neutral?
Apple juice 3.80
Soy milk neutral
Tuna (canned) 6.3×107M
A) Calculate the [H3O+] of apple juice with pH=3.80 .
Express the molarity to two significant figures.
B) Calculate the [OH] of apple juice with pH=3.80 .
Express the molarity to two significant figures.
C) Calculate the [H3O+] of soy milk.
Express the molarity to two significant figures.
D) Calculate the [OH] of soy milk.
Express the molarity to two significant figures.
E) Calculate the pH of soy milk.
Express the pH to two decimal places.
F) Calculate the [OH] of tuna (canned) with [H3O+] = 6.3×107M .
Express the molarity to two significant figures.
G) Calculate the pH of tuna (canned) with [H3O+] = 6.3×107M .
Express the pH to two decimal places.
Explanation / Answer
A) pH =-log[H3O+]
3.80=-log[H3O+]
-3.80= log[H3O+]
10-3.8 =[H3O+]
[H3O+] =1.58x10-4 M
B) pH + pOH = 14
3.8 + pOH =14
pOH= 10.2
pOH=-log[OH-]
-10.2= log[OH-]
10-10.2 = [OH-]
[OH-] = 6.31x10-11 M
C) If the milk is neutral, its pH is 7.
pH =-log[H3O+]
7=-log[H3O+]
-7= log[H3O+]
10-7 =[H3O+]
[H3O+] =1.00x10-7 M
D) pH + pOH = 14
7 + pOH =14
pOH= 7
pOH=-log[OH-]
-7= log[OH-]
10-7 = [OH-]
[OH-] = 1.00x10-7 M
E) If the milk is neutral, its pH is 7.00.
F) pH =-log[H3O+]
pH =-log 6.3x10-7
pH=6.20
pH + pOH = 14
6.20 + pOH =14
pOH= 7.80
pOH=-log[OH-]
-7.80= log[OH-]
10-7.80 = [OH-]
[OH-] = 1.58x10-8 M
G) pH =-log[H3O+]
pH =-log 6.3x10-7
pH=6.20