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Post Lecture Homework Chapter 18-Google Chrome https://s ingchemistry.com/myct/i

ID: 1055254 • Letter: P

Question

Post Lecture Homework Chapter 18-Google Chrome https://s ingchemistry.com/myct/itemView?assignmentProblemID-67394223 016 Introducton to the Nernet Equation introduction to the Nernst Equation Consder ihe necton at 75 C wher Fe Part A Learning Geal Te leam how to use She Nenst equsion Me(s) 3 20 M and ME1210 M Express your anawer numericalhy potenitial in vots R 8.314 J/(K ol) is the ges 3.2 incorrect: Try Again;5 attempts remaining Part B What s the vaue for the tempertue T nkalvins? Express your answer to thee significant Sgures and include the apprepriate usits Correct Part.c

Explanation / Answer

The equilibrium constant and the reaction quotient have the same expression.

The given reaction is Mg + Fe+2  ------> Mg +2 + Fe

Thus K (Q) = [Mg+2] /[Fe+2] as the concentration os solid is unity

Given [MG+2] = 0.210M and [Fe+2] = 3.2 M

Hence Q = 0.21 /3.2 =0.0656 = 6.56x 10-2

Part B

The temperature in Kelvin = 75 + 273 = 348 K

Part C

The number of electrons transfered is "n"

In this reaction Fe+2 is reduced to Fe and Mg is oxidised to Mg+2

Thus n value is 2 electrons

Part D

Standard cell potential = SRP of Fe - SRP of Mg

= -0.44 -(-2.36)

= 1.92 V