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Consider the following pairs of the liquids CH_3CH_2CH_2CH_2CH_3 and CH_3CH_2CH_

ID: 1055792 • Letter: C

Question

Consider the following pairs of the liquids CH_3CH_2CH_2CH_2CH_3 and CH_3CH_2CH_2CH_2CH_3 and CH_3OH CH_3CH_2CH_2CH_2CH_3 and H_2O For which pairs woul a homogenous solution be expected when equal volumes of liquids are mixed? Pair (i) would form a homogenous solution Pair (ii) would form a homogenous solution Pair (iii) would form a homogenous solution Pair (i) and (iii) would form a homogenous solution No pairs would form homogenous solutions. Of the following is an exothermic process boiling subliming melting freezing All of the above are exothermic

Explanation / Answer

Question 6

PV = nRT

where:

P is the pressure of the gas = 1.1 atm .

V is the volume of the gas = 0.43 Liter

n is the amount of substance of gas (in moles) = ?

R is gas constant, = 0.0821 L atm K-1 Mol-1

T is the absolute temperature of the gas. = 273.15 +20 = 293.15

substitute in the equation and calculate n

n = 1.1 x 0.43 / 0.0821 x 293. 15 = 0.01965 Moles

Using n Find the volume of the gas

V = 0.01965 x 0.0821 x 303.15 / 1.25 = 0.391 liter or 391 ml

Option D is the answer

Question 7

Option D is the answer

Pair i and Pair II would form the homogeneous mixture

Question 8

Option D is the answer

Freezing is an exothermic process

(https://socratic.org/questions/why-is-freezing-an-exothermic-process)