A sample of ideal gas at room temperature occupies a volume of 12.0 L at a press

Question

A sample of ideal gas at room temperature occupies a volume of 12.0 L at a pressure of 392 torr. If the pressure changes to 1960 torr, with no change in the temperature or moles of gas, what is the new volume V_2? Express your answer with the appropriate units. If the volume of the original sample in Part A (P_1 = 392 torr, V_1 = 12.0 L) changes to 65.9 L, without a change in the temperature or moles of gas molecules, what is the new pressure, P_2? Express your answer with the appropriate units.

Explanation / Answer

A) P1V1 /T1   = P2V2/T2

as temperature is constant

P1V1 = P2V2

P1 = 392 torr = 0.516 atm   , V1 = 12.0 L

P2 = 1960 torr = 2.579 atm   , V2 = ?

V2 = (P1V1 / P2)

V2 = (0.516 x 12 / 2.579)

V2 = 6.192 / 2.579

V = 2.4 L

B) P2 = (P1V1/V2)

P2 = (0.516 x12 / 65 )

P2 = 0.095 atm

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