Consider the formula delta G = delta Go + RT In Q. If the system is at equilibri

Question

Consider the formula delta G = delta Go + RT In Q. If the system is at equilibrium, which is true? Q = K delta G = 0 delta Go = 0 a and b a and c For a non ideal gas, which of these expressions represents activity? p/pouf/poi p f For the following reaction, which of these substances would not appear in the equilibrium constant expression? Br_2 (aq) + H_2 O (l) = HOBr (aq) + H+ (aq) + Br- (aq) Br_2 H_2 O HOBr Br- If one integrates the expression integral dT/T^2 between the limits T_2 and T_1, one gets: In^2 T_2/T_2 (1/T_2 - 1/T_1) -(1/T_2 - 1/T_1) -2(1/T_2 - 1/T_1) Ln (K_2/K_1) can also be written as: In K_2/K_1 K_2;/ln K_1 In K_2 - ln K_1 ln K_2 - K_1 If the activity of an NaOH solution is 2.7 c) 5.7 and its concentration is 3.00 m, the activity coefficient equals: 0.9 1.1 5.7 0.3 Consider the reversible reaction N_2 + 3H_2 = 2NH_3 All of these substances are gases. If one decreased the volume, thus increased the pressure, which statement is true: the equilibrium would shift towards products the equilibrium would shift towards reactants the equilibrium would not shift at all a different chemical reaction would occur

Explanation / Answer

If system is at equilibrium chemical reaction quotient "Q" is equal to equlibrium constant "K" we are at equilibrium, the amounts of products and reactants in the mixture are fixed. Total gibbs free energy(G) is zero when a a reaction is at equilibrium. So the answere is option "d) a and b"`

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