If you were to use 5.0 mmol of tert- butanol (A) for the reaction, how much of i

Question

If you were to use 5.0 mmol of tert- butanol (A) for the reaction, how much of it would you measure out? 0.37 mL 0.48 mL 0.76 mL 1.3 mL What is the theoretical yield of the product if you performed the reaction with 5.0 mmol of tert- butanol in excess HCl? 0.37 g 0.74 g 0.46 g 1.3 g How would you purify a liquid mixture containing both A and B to obtain pure B? recrystallization sublimation column chromatography more than one of the previous The alkyl chloride synthesis reaction shown follows the mechanism. S_N 1 S_N 2 E1 E2

Explanation / Answer

Q27

m = 5*10^-3 mol

mass = mol*MW = (5*10^-3)(74.12) = 0.3706 g of tert-butanol

V = mass/D = 0.3706 / 0.78 = 0.47512 mL required, choose B

Q28

theoretical yield

rati ois 1:1 mol

so

5 mmol of alcohol will give us 5 mmol of chloroalkane

mass = mol*MW = (5*10^-3)*92.57 = 0.46285 g ; choose C

Q29

For A B purification...

this could be via --> column chromatography, since their polarities are different

Q30

this is SN1 since this is a substitution, and it is done in a single step leaving group moving out

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